Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 795: 30


$a_8=27\sqrt 3$

Work Step by Step

$a_n=a_1r^{n-1}$ $a_1=1,~~r=\sqrt 3$ $a_8=1(\sqrt 3)^{8-1}=1(\sqrt 3)^7=\sqrt {3^7}=\sqrt {3^6(3)}=3^3\sqrt 3=27\sqrt 3$
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