Answer
$a_8=27\sqrt 3$
Work Step by Step
$a_n=a_1r^{n-1}$
$a_1=1,~~r=\sqrt 3$
$a_8=1(\sqrt 3)^{8-1}=1(\sqrt 3)^7=\sqrt {3^7}=\sqrt {3^6(3)}=3^3\sqrt 3=27\sqrt 3$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 795: 30
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