Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 795: 32

Answer

$a_n=1000(1.005)^{n-1}$ $a_{60}=1342.14$

Work Step by Step

$a_n=a_1r^{n-1}$ $a_n=1000(1.005)^{n-1}$ $a_{60}=1000(1.005)^{60-1}=1000(1.005)^{59}=1342.14$
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