Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 795: 31


$a_n=500(1.02)^{n-1}$ $a_{40}=1082.37$

Work Step by Step

$a_n=a_1r^{n-1}$ $a_n=500(1.02)^{n-1}$ $a_{40}=500(1.02)^{40-1}=500(1.02)^{39}=1082.37$
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