Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 795: 37



Work Step by Step

$a_1=5$ $r=\frac{a_2}{a_1}=\frac{a_3}{a_2}$ $r=\frac{-9}{6}=\frac{\frac{27}{2}}{-9}=-\frac{3}{2}$ $a_n=a_1r^{n-1}$ $a_n=6(-\frac{3}{2})^{n-1}=6(-\frac{3}{2})^n(-\frac{3}{2})^{-1}=6(-\frac{3}{2})^n(-\frac{2}{3})=-4(-\frac{3}{2})^n$
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