Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 795: 35


$a_n= \frac{9}{2}(2)^n$

Work Step by Step

$a_1=9$ $r=\frac{a_2}{a_1}=\frac{a_3}{a_2}$ $r=\frac{18}{9}=\frac{36}{18}=2$ $a_n=a_1r^{n-1}$ $a_n=9(2)^{n-1}=9(2)^n(2^{-1})=9(2)^n\frac{1}{2}=\frac{9}{2}(2)^n$
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