Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 795: 29


$a_{12}=32\sqrt 2$

Work Step by Step

$a_n=a_1r^{n-1}$ $a_1=1,~~r=\sqrt 2$ $a_{12}=1(\sqrt 2)^{12-1}=1(\sqrt 2)^{11}=\sqrt {2^{11}}=\sqrt {2^{10}(2)}=2^5\sqrt 2=32\sqrt 2$
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