Answer
$a_n=(-1)^{n+1}$
Work Step by Step
$a_1=1=(-1)^2=(-1)^{1+1}$
$a_2=-1=(-1)^3=(-1)^{1+2}$
$a_3=1=(-1)^4=(-1)^{1+3}$
$a_4=-1=(-1)^5=(-1)^{1+4}$
$a_5=1=(-1)^6=(-1)^{1+5}$
It is easy to conclude that: $a_n=(-1)^{n+1}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 777: 41
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