Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 777: 41



Work Step by Step

$a_1=1=(-1)^2=(-1)^{1+1}$ $a_2=-1=(-1)^3=(-1)^{1+2}$ $a_3=1=(-1)^4=(-1)^{1+3}$ $a_4=-1=(-1)^5=(-1)^{1+4}$ $a_5=1=(-1)^6=(-1)^{1+5}$ It is easy to conclude that: $a_n=(-1)^{n+1}$
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