## Algebra and Trigonometry 10th Edition

$a_n=\frac{8}{n+1}$ $a_1=\frac{8}{1+1}=\frac{8}{2}=4$ $a_2=\frac{8}{1+2}=\frac{8}{3}$ $a_2=\frac{8}{1+3}=\frac{8}{4}=2$ ... $a_7=\frac{8}{1+7}=\frac{8}{8}=1$ ... $a_{10}=\frac{8}{10+1}=\frac{8}{11}$ The graph labeled as (c) matches the sequence.