## Algebra and Trigonometry 10th Edition

$a_n=\frac{8n}{n+1}$ $a_1=\frac{8(1)}{1+1}=\frac{8}{2}=4$ $a_2=\frac{8(2)}{1+2}=\frac{16}{3}$ $a_2=\frac{8(3)}{1+3}=\frac{24}{4}=6$ ... $a_7=\frac{8(7)}{1+7}=\frac{56}{8}=7$ ... $a_{10}=\frac{8(10)}{10+1}=\frac{80}{11}$ As $n$ grows, the sequence approaches 8. The graph labeled as b matches the sequence.