Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 777: 15

Answer

$a_1=\frac{1}{3}$ $a_2=\frac{8}{3}$ $a_3=9$ $a_4=\frac{64}{3}$ $a_5=\frac{125}{3}$

Work Step by Step

$a_n=\frac{1}{3}n^3$ $a_1=\frac{1}{3}(1)^3=\frac{1}{3}(1)=\frac{1}{3}$ $a_2=\frac{1}{3}(2)^3=\frac{1}{3}(8)=\frac{8}{3}$ $a_3=\frac{1}{3}(3)^3=\frac{1}{3}(27)=\frac{27}{3}=9$ $a_4=\frac{1}{3}(4)^3=\frac{1}{3}(64)=\frac{64}{3}$ $a_5=\frac{1}{3}(5)^3=\frac{1}{3}(125)=\frac{125}{3}$
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