Answer
$\begin{bmatrix}
-4 & 10\\
3 & 14\\
\end{bmatrix}$
Work Step by Step
First add the two matrices within the parentheses:
$\begin{bmatrix}
4-2 & 0+3\\
0-3 & -1+5\\
-1+0 & 2-3\\
\end{bmatrix}$ = $\begin{bmatrix}
2 & 3\\
-3 & 4\\
-1 & -1\\
\end{bmatrix}$
Then multiply the matrix outside the parentheses with the matrix found above:
$\begin{bmatrix}
0 & 2 & -2\\
4 & 1 & 2\\
\end{bmatrix}$$\begin{bmatrix}
2 & 3\\
-3 & 4\\
-1 & -1\\
\end{bmatrix}$ = $\begin{bmatrix}
0(2) + 2(-3) + (-2)(-1) & 0(3) + 2(4) + (-2)(-1)\\
4(2) + 1(-3) + 2(-1) & 4(3) + 1(4) + 2(-1)\\
\end{bmatrix}$ = $\begin{bmatrix}
0-6+2 & 0+8+2\\
8-3-2 & 12+4-2\\
\end{bmatrix}$ = $\begin{bmatrix}
-4 & 10\\
3 & 14\\
\end{bmatrix}$
