## Algebra and Trigonometry 10th Edition

$\begin{bmatrix} 27 & -6\\ -6 & -27\\ \end{bmatrix}$
First multiply the two matrices: $\begin{bmatrix} 6(0) + 5(-1) + (-1)(4) & 6(3) + 5(-3) + (-1)(1)\\ 1(0) + (-2)(-1) + 0(4) & 1(3) + (-2)(-3) + 0(1)\\ \end{bmatrix}$ = $\begin{bmatrix} 0-5-4 & 18-15-1\\ 0+2+0 & 3+6+0\\ \end{bmatrix}$ = $\begin{bmatrix} -9 & 2\\ 2 & 9\\ \end{bmatrix}$ Then multiply the matrix found above by the scalar multiple -3: $\begin{bmatrix} -9(-3) & 2(-3)\\ 2(-3) & 9(-3)\\ \end{bmatrix}$ = $\begin{bmatrix} 27 & -6\\ -6 & -27\\ \end{bmatrix}$