## Algebra and Trigonometry 10th Edition

X = $\begin{bmatrix} -1 & \frac{3}{2} & -\frac{1}{2}\\ 1 & 0 & \frac{5}{2}\\ \end{bmatrix}$
2X = A + B X = $\frac{1}{2}$(A + B) First perform A + B to get matrix Y: Y = $\begin{bmatrix} -2+0 & 1+2 & 3-4\\ -1+3 & 0+0 & 4+1\\ \end{bmatrix}$ = $\begin{bmatrix} -2 & 3 & -1\\ 2 & 0 & 5\\ \end{bmatrix}$ Then multiply matrix Y by the scalar multiple of $\frac{1}{2}$ to get X: X = $\begin{bmatrix} -2(\frac{1}{2}) & 3(\frac{1}{2}) & -1(\frac{1}{2})\\ 2(\frac{1}{2}) & 0(\frac{1}{2}) & 5(\frac{1}{2})\\ \end{bmatrix}$ = $\begin{bmatrix} -1 & \frac{3}{2} & -\frac{1}{2}\\ 1 & 0 & \frac{5}{2}\\ \end{bmatrix}$