## Algebra and Trigonometry 10th Edition

X = $\begin{bmatrix} -2 & 0 & 5\\ -\frac{5}{2} & 0 & \frac{7}{2}\\ \end{bmatrix}$
2X = 2A - B X = $\frac{1}{2}$(2A - B) First multiply matrix A by the scalar multiple 2: $\begin{bmatrix} -2(2) & 1(2) & 3(2)\\ -1(2) & 0(2) & 4(2)\\ \end{bmatrix}$ = $\begin{bmatrix} -4 & 2 & 6\\ -2 & 0 & 8\\ \end{bmatrix}$ Then perform 2A - B to get matrix Y: Y = $\begin{bmatrix} -4-0 & 2-2 & 6+4\\ -2-3 & 0-0 & 8-1\\ \end{bmatrix}$ = $\begin{bmatrix} -4 & 0 & 10\\ -5 & 0 & 7\\ \end{bmatrix}$ Then multiply matrix Y by the scalar multiple of $\frac{1}{2}$ to get X: X = $\begin{bmatrix} -4(\frac{1}{2}) & 0(\frac{1}{2}) & 10(\frac{1}{2})\\ -5(\frac{1}{2}) & 0(\frac{1}{2}) & 7(\frac{1}{2})\\ \end{bmatrix}$ = $\begin{bmatrix} -2 & 0 & 5\\ -\frac{5}{2} & 0 & \frac{7}{2}\\ \end{bmatrix}$