Answer
X = $\begin{bmatrix}
-6 & -1 & 17\\
-9 & 0 & 10\\
\end{bmatrix}$
Work Step by Step
X = 3A - 2B
First multiply matrix A by the scalar multiple 3:
$\begin{bmatrix}
-2(3) & 1(3) & 3(3)\\
-1(3) & 0(3) & 4(3)\\
\end{bmatrix}$ = $\begin{bmatrix}
-6 & 3 & 9\\
-3 & 0 & 12\\
\end{bmatrix}$
Next, multiply matrix B by the scalar multiple 2:
$\begin{bmatrix}
0(2) & 2(2) & -4(2)\\
3(2) & 0(2) & 1(2)\\
\end{bmatrix}$ = $\begin{bmatrix}
0 & 4 & -8\\
6 & 0 & 2\\
\end{bmatrix}$
Then perform X = 3A - 2B:
X = $\begin{bmatrix}
-6-0 & 3-4 & 9+8\\
-3-6 & 0-0 & 12-2\\
\end{bmatrix}$ = $\begin{bmatrix}
-6 & -1 & 17\\
-9 & 0 & 10\\
\end{bmatrix}$
