Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 10 - 10.2 - Operations with Matrices - 10.2 Exercises - Page 724: 27

Answer

X = $\begin{bmatrix} -4 & 6 & -2\\ 4 & 0 & 10\\ \end{bmatrix}$

Work Step by Step

X = 2A + 2B First multiply matrix A by the scalar multiple 2: $\begin{bmatrix} -2(2) & 1(2) & 3(2)\\ -1(2) & 0(2) & 4(2)\\ \end{bmatrix}$ = $\begin{bmatrix} -4 & 2 & 6\\ -2 & 0 & 8\\ \end{bmatrix}$ First multiply matrix B by the scalar multiple 2: $\begin{bmatrix} 0(2) & 2(2) & -4(2)\\ 3(2) & 0(2) & 1(2)\\ \end{bmatrix}$ = $\begin{bmatrix} 0 & 4 & -8\\ 6 & 0 & 2\\ \end{bmatrix}$ Then perform X = 2A + 2B: X = $\begin{bmatrix} -4+0 & 2+4 & 6-8\\ -2+6 & 0+0 & 8+2\\ \end{bmatrix}$ = $\begin{bmatrix} -4 & 6 & -2\\ 4 & 0 & 10\\ \end{bmatrix}$
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