Answer
$x^4-20x^2-576=0$
Work Step by Step
$x=4i,-4i,6,-6$
$(x-4i)(x+4i)(x-6)(x+6)=0$,
$(x^2-16i^2)(x^2-36)=0, i^2=-1$
$(x^2+16)(x^2-36)=0$
Therefore, multiplying out the factors:
$x^4-36x^2+16x^2-576=0$
$x^4-20x^2-576=0$
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