Answer
$21x^2+31x-42=0$
Work Step by Step
$x=-\frac{7}{3}$ and $x=\frac{6}{7}$.
$x+\frac{7}{3}=0$ and $x-\frac{6}{7}=0$.
$(x+\frac{7}{3})(x-\frac{6}{7})=0$
$(3x+7)(7x-6)=0$
$21x^2+31x-42=0$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 129: 85
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
