Answer
$x^4-1=0$
Work Step by Step
$x=-1,1,-i,i$
$(x-1)(x+1)(x-i)(x+i)=0$
$(x^2-1)(x^2-i^2)=0, i^2=-1$
$(x^2-1)(x^2+1)=0$
Therefore, multiplying out the factors.
$x^4+x^2-x^2-1=0$
$x^4-1=0$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 129: 91
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