Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 129: 78

Answer

$x=0.826$ or $x=-0.807$

Work Step by Step

$5.25x^6-0.2x^3-1.55=0$ Let $x^3=a$. $5.25a^2-0.2a-1.55=0$ Multiplying both sides of the equation by 100: $525a^2-20a-155=0$ Using the quadratic formula for the quadratic equation. $a=\frac{20\pm \sqrt{(20)^2+4(525)(155)}}{2\times525}=\frac{20 \pm \sqrt{325900}}{1050}$ Thus, $a=0.563$ or $a=-0.525$. Since $x^3=a$, $x=\sqrt[3] {0.563}=0.826$ or $x=\sqrt[3] {-0.525}=-0.807$
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