Answer
$40x^2+37x+4=0$
Work Step by Step
$x=-\frac{1}{8}$ and $x=-\frac{4}{5}$
$x+\frac{1}{8}=0$ and $x+\frac{4}{5}=0$,
$(x+\frac{1}{8})(x+\frac{4}{5})=0$
Therefore, multiplying the factors.
$(8x+1)(5x+4)=0$
$40x^2+37x+4=0$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 129: 86
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