## Algebra and Trigonometry 10th Edition

Solve : $\frac{x}{x^{2}-3x} + \frac{4}{x} = \frac{1}{x-3}$ $\frac{x}{x(x-3)} + \frac{4}{x} = \frac{1}{x-3}$ Multiplying both sides with x(x-3) x + 4(x-3) = x 4(x-3) = 0 x = 3 Plug x=3 into the expression. Division by zero is undefined, so x=3 is extraneous.