# Chapter 1 - 1.2 - Linear Equations in One Variable - 1.2 Exercises - Page 87: 43

No Solution

#### Work Step by Step

Solve : $\frac{x}{x^{2}-3x} + \frac{4}{x} = \frac{1}{x-3}$ $\frac{x}{x(x-3)} + \frac{4}{x} = \frac{1}{x-3}$ Multiplying both sides with x(x-3) x + 4(x-3) = x 4(x-3) = 0 x = 3 Plug x=3 into the expression. Division by zero is undefined, so x=3 is extraneous.

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