Algebra and Trigonometry 10th Edition

Solve : $2 \div ((x-4)(x-2)) = 1/(x-4) + 2/(x-2)$ $2 \div ((x-4)(x-2)) = (x-2 + 2(x-4) ) \div ((x-4)(x-2))$ 2 = x - 2 + 2x -8 2 = 3x - 10 3x = 12 x=4 Plug in the x=4 and the denominator becomes zero and since division by zero is not defined, x=4 is an extraneous solution.