## Algebra and Trigonometry 10th Edition

$x\ne1,-3$ because the denominators cannot be equal to $0$. After multiplying both sides by $(x-1)(x+3):$ $12=3(x+3)+2(x-1)\\12=3x+9+2x-2\\12=5x+7\\5=5x\\x=1$ But $x\ne1$ from earlier. Thus there is no solution.