## Algebra and Trigonometry 10th Edition

Solve : 1/x + 2/(x-5) = 0 $(x - 5 + 2x) \div (x(x-5))$ = 0 x - 5 + 2x = 0; 3x = 5 x = 5/3 Check : LHS = 1/x + 2/(x-5) = 3/5 + 2/(5/3 - 5) = 3/ 5 - 6/10 = 3/5 - 3/5 = 0 RHS = 0 LHS = RHS, Hence Verified