## Algebra and Trigonometry 10th Edition

The graph of $x(\frac{520}{3}-x)$ with $0\lt x\lt\frac{520}{3}$
$y=\frac{520}{3}-x$ The dimensions must be positive numbers. That is, $x\gt0$ and $y\gt0$ $y\gt0$ $\frac{520}{3}-x\gt0$ $-x\gt\frac{520}{3}$ $x\lt\frac{520}{3}$ So: $0\lt x\lt\frac{520}{3}$