Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.1 - Graphs of Equations - 1.1 Exercises - Page 79: 75b

Answer

See explanation

Work Step by Step

Using the formula for the perimeter of a rectangle: $$P=2(x+y)$$ Substituting $P=\frac{1040}{3}$: $$\frac{1040}{3}=2(x+y)$$ Simplifying: $$\frac{\frac{1040}{3}}{2}=x+y$$ $$\frac{520}{3}=x+y$$ $$\frac{520}{3}-x=y$$ Then, $$y=\frac{520}{3}-x$$ Using the formula for the area of a rectangle: $$A=xy$$ Substituting $y=\frac{520}{3}-x$, then: $$A=x\left(\frac{520}{3}-x\right)$$
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