Answer
$(x-1)^2+(y+3)^2=11$
Work Step by Step
The standard form of a circle with center at $(h,k)$ and radius $r$ is:
$$(x-h)^2+(y-k)^2=r^2$$
Substituting $h=1$, $k=-3$ and $r=\sqrt {11}$:
$$(x-1)^2+[y-(-3)]^2=(\sqrt {11})^2$$ Simplifying:
$$(x-1)^2+(y+3)^2=11$$
