## Algebra and Trigonometry 10th Edition

$(x+2)^2+(y+6)^2=25$
Center: $(h,k)=(-2,-6)$ The distance from the center to the solution point is the radius: $r=\sqrt {(-2-1)^2+[-6-(-10)]^2}=\sqrt {9+16}=\sqrt {25}=5$ Equation of a circle: $(x−h)^2+(y−k)^2=r^2$ (standard form) $[(x-(-2)]^2+[y-(-6)]^2=5^2$ $(x+2)^2+(y+6)^2=25$