Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.1 - Graphs of Equations - 1.1 Exercises - Page 79: 64

Answer

$(x+2)^2+(y+6)^2=25$

Work Step by Step

Center: $(h,k)=(-2,-6)$ The distance from the center to the solution point is the radius: $r=\sqrt {(-2-1)^2+[-6-(-10)]^2}=\sqrt {9+16}=\sqrt {25}=5$ Equation of a circle: $(x−h)^2+(y−k)^2=r^2$ (standard form) $[(x-(-2)]^2+[y-(-6)]^2=5^2$ $(x+2)^2+(y+6)^2=25$
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