Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.1 - Graphs of Equations - 1.1 Exercises - Page 79: 63



Work Step by Step

Center: $(h,k)=(3,8)$ The distance from the center to the solution point is the radius: $r=\sqrt {[3-(-9)]^2+(8-13)^2}=\sqrt {144+25}=\sqrt {169}=13$ Equation of a circle: $(x−h)^2+(y−k)^2=r^2$ (standard form) $(x-3)^2+(y-8)^2=13^2$ $(x-3)^2+(y-8)^2=169$
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