Appendix A - A Exercises - Page A6: 30

It is verified that the two expressions are equivalent. $\frac{4x}{14}-2y^2=\frac{2x^2}{7}-\frac{y^2}{\frac{1}{2}}$

Work Step by Step

$\frac{4x}{14}-2y^2=\frac{4x}{14}\frac{\frac{1}{2}}{\frac{1}{2}}-2y^2\frac{\frac{1}{2}}{\frac{1}{2}}=\frac{2x^2}{7}-\frac{y^2}{\frac{1}{2}}$

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