Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Appendix A - A Exercises - Page A6: 22

Answer

$$x^{\frac{1}{2}}(10x+3)$$

Work Step by Step

$3(2x+1)x^{\frac{1}{2}}+4x^{\frac{3}{2}}=3(2x+1)x^{\frac{1}{2}}+4x^{\frac{1}{2}+1}=(6x+3)x^{\frac{1}{2}}+4x(x^{\frac{1}{2}})=x^{\frac{1}{2}}(6x+3+4x)=x^{\frac{1}{2}}(10x+3)$
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