# Appendix A - A Exercises - Page A6: 12

$5+(1/y)=\frac{5y+1}{y}$

#### Work Step by Step

$5=\frac{5}{1}$. So, the 5 is not in the denominator. Also, suppose the five is in the denominator: $\frac{1}{5}$. Before proceeding with the sum, the LCD should be evaluated. Correct procedure: $5+(1/y)=\frac{5}{1}+\frac{1}{y}=\frac{5y}{y}+\frac{1}{y}=\frac{5y+1}{y}$

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