## Algebra and Trigonometry 10th Edition

It is verified that the two expressions are equivalent. $\frac{x^2}{\frac{1}{4}}+\frac{3y^2}{5}=4x^2+\frac{6y^2}{10}$
Start on the right side: $\frac{x^2}{\frac{1}{4}}+\frac{3y^2}{5}=\frac{x^2}{\frac{1}{4}}\frac{4}{4}+\frac{3y^2}{5}\frac{2}{2}=4x^2+\frac{6y^2}{10}$