Answer
It is verified that the two expressions are equivalent.
$\frac{5x^2}{9}-\frac{16y^2}{49}=\frac{x^2}{\frac{9}{5}}-\frac{y^2}{\frac{49}{16}}$
Work Step by Step
$\frac{5x^2}{9}-\frac{16y^2}{49}=\frac{5x^2}{9}\frac{\frac{1}{5}}{\frac{1}{5}}-\frac{16y^2}{49}\frac{\frac{1}{16}}{\frac{1}{16}}=\frac{x^2}{\frac{9}{5}}-\frac{y^2}{\frac{49}{16}}$
