Answer
2
Work Step by Step
$\frac{8x+7}{3x+5}$-$\frac{2x-3}{3x+5}$=
$\frac{8x+7-(2x-3)}{3x+5}$=
$\frac{8x+7-2x+3}{3x+5}$=
$\frac{6x+10}{3x+5}$=$\frac{2(3x+5)}{3x+5}$ = 2
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