Answer
$z$
Work Step by Step
$\frac{2z^2}{4z-1} - \frac{z-2z^2}{4z-1} = \frac{2z^2-(z-2z^2)}{4z-1} = \frac{2z^2-z+ 2z^2}{4z-1} = \frac{4z^2-z}{4z-1} = \frac{z(4z-1)}{4z-1} = z$
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