Answer
$\frac{4x+2}{(2x-1)(x+3)}$
Work Step by Step
$\frac{4}{2x^2+5x-3}+\frac{2}{x+3}$
$\frac{4}{(2x-1)(x+3)}+\frac{2}{x+3}$
$\frac{4}{(2x-1)(x+3)}+\frac{2*(2x-1)}{(2x-1)(x+3)}$
$\frac{4}{(2x-1)(x+3)}+\frac{4x-2}{(2x-1)(x+3)}$
$\frac{4x+2}{(2x-1)(x+3)}$