Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set - Page 517: 81

Answer

$\frac{2(x-8)}{(x-4)(x+4)}$

Work Step by Step

$\frac{3}{x+4}=\frac{1}{x-4}+y$ $\frac{3(x-4)}{(x+4)(x-4)}=\frac{1(x+4)}{(x-4)(x+4)}+y$ $\frac{3x-12}{(x+4)(x-4)}=\frac{x+4}{(x-4)(x+4)}+y$ $\frac{3x-12}{(x+4)(x-4)}=\frac{x+4}{(x-4)(x+4)}+\frac{y}{(x-4)(x+4)}$ $3x-12=x+4+y$ $2x-16=y$
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