Answer
$\frac{6x^{2}-5x-3}{x(x+1)(x-1)}$
Work Step by Step
$\frac{3}{x}$ -$\frac{2x}{x^{2}-1}$+$\frac{5}{x+1}$=
$\frac{3}{x}$ -$\frac{2x}{(x+1)(x-1)}$+$\frac{5}{x+1}$=
$\frac{3(x+1)(x-1)}{x(x+1)(x-1)}$ -$\frac{2xx}{x(x+1)(x-1)}$+$\frac{5x(x-1)}{x(x+1)(x-1)}$=
$\frac{3(x+1)(x-1)-2xx+5x(x-1)}{x(x+1)(x-1)}$ =
$\frac{3(x^{2}-1)-2x^{2}+5x^{2}-5x}{x(x+1)(x-1)}$ =
$\frac{3x^{2}-3+3x^{2}-5x}{x(x+1)(x-1)}$ =
$\frac{6x^{2}-5x-3}{x(x+1)(x-1)}$ =
