Answer
$\frac{25a}{9(a-2)}$
Work Step by Step
$\frac{5a+10}{18}$ $\div$ $\frac{a^{2}-4}{10a}$=
$\frac{5(a+2)}{18}$ $\times$ $\frac{10a}{a^{2}-4}$=
$\frac{5(a+2)}{18}$ $\times$ $\frac{10a}{(a+2)(a-2)}$=
$\frac{5(a+2)10a}{18(a+2)(a-2)}$ =$\frac{5*10a}{18(a-2)}$=
$\frac{50a}{18(a-2)}$=$\frac{25a}{9(a-2)}$
