Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set - Page 516: 62



Work Step by Step

$\frac{9z+5}{15}$$\times$$\frac{5z}{81z^{2}-25}$= $\frac{9z+5}{15}$$\times$$\frac{5z}{(9z+5)(9z-5)}$= $\frac{(9z+5)5z}{15(9z+5)(9z-5)}$=$\frac{5z}{15(9z-5)}$= $\frac{z}{3(9z-5)}$
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