Answer
$\dfrac{-7}{y^{2}-3y+2}-\dfrac{2}{y-1}=-\dfrac{2y+3}{(y-2)(y-1)}$
Work Step by Step
$\dfrac{-7}{y^{2}-3y+2}-\dfrac{2}{y-1}$
Factor the denominator of the first fraction:
$\dfrac{-7}{y^{2}-3y+2}-\dfrac{2}{y-1}=\dfrac{-7}{(y-2)(y-1)}-\dfrac{2}{y-1}=...$
Evaluate the substraction of the two rational expressions:
$...=\dfrac{-7-2(y-2)}{(y-2)(y-1)}=\dfrac{-7-2y+4}{(y-2)(y-1)}=\dfrac{-2y-3}{(y-2)(y-1)}=...$
$...=-\dfrac{2y+3}{(y-2)(y-1)}$
