Answer
$\frac{x(8x-17)}{(x-10)(x-3)}$
Work Step by Step
$\frac{9x}{x-10}$-$\frac{x}{x-3}$=
$\frac{9x(x-3)}{(x-10)(x-3)}$-$\frac{x(x-10)}{(x-3)(x-10)}$=
$\frac{9x(x-3)-x(x-10)}{(x-10)(x-3)}$=
$\frac{9x^{2}-27x-x^{2}+10x}{(x-10)(x-3)}$
$\frac{8x^{2}-17x}{(x-10)(x-3)}$=$\frac{x(8x-17)}{(x-10)(x-3)}$