Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set: 38

Answer

$\frac{x(8x-17)}{(x-10)(x-3)}$

Work Step by Step

$\frac{9x}{x-10}$-$\frac{x}{x-3}$= $\frac{9x(x-3)}{(x-10)(x-3)}$-$\frac{x(x-10)}{(x-3)(x-10)}$= $\frac{9x(x-3)-x(x-10)}{(x-10)(x-3)}$= $\frac{9x^{2}-27x-x^{2}+10x}{(x-10)(x-3)}$ $\frac{8x^{2}-17x}{(x-10)(x-3)}$=$\frac{x(8x-17)}{(x-10)(x-3)}$
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