Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set: 37

Answer

$\frac{x(x+3)}{(x-2)(x-7)}$

Work Step by Step

$\frac{2x}{x-7}$-$\frac{x}{x-2}$= $\frac{2x(x-2)}{(x-7)(x-2)}$-$\frac{x(x-7)}{(x-2)(x-7)}$= $\frac{2x(x-2)-x(x-7)}{(x-2)(x-7)}$= $\frac{2x^{2}-4x-x^{2}+7x}{(x-2)(x-7)}$ $\frac{x^{2}+3x}{(x-2)(x-7)}$=$\frac{x(x+3)}{(x-2)(x-7)}$
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