Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.3 - Adding and Subtracting Rational Expressions with the Same Denominator and Least Common Denominator - Exercise Set - Page 508: 44

Answer

$5x^2 - 25x$

Work Step by Step

Let's simplify the first fraction. When we do that, we get $\frac{5}{x^{2} + 2x -3}$ Now, if we use the factoring method for the denominator, we get $\frac{5}{(x+3)(x-1)}$ So now, this is what we have $\frac{5}{(x+3)(x-1)} = \frac{?}{x(x-1)(x-5)(x+3)}$ Now multiply both sides by $(x+3)(x-1)$ $\frac{5}{1} = \frac{?}{x(x-5)}$ Now, let's cross multiply $5x(x-5) =?$ $? = 5x^2 - 25x$
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