Chapter 7 - Section 7.3 - Adding and Subtracting Rational Expressions with the Same Denominator and Least Common Denominator - Exercise Set - Page 508: 43

$\frac{x(x+1)}{(x)(x+2)(x+4)(x+1)}$

$\frac{x}{x^3+6x^2+8x}$ $x^3+6x^2+8x$ $x(x^2+6x+8)$ $x(x+2)(x+4)$ $\frac{x}{x^3+6x^2+8x} = \frac{x}{(x)(x+2)(x+4)}$ $\frac{x}{(x)(x+2)(x+4)}=\frac{x*(x+1)}{(x)(x+2)(x+4)*(x+1)}$ $\frac{x(x+1)}{(x)(x+2)(x+4)(x+1)}$