Answer
$\frac{24y^{4}}{72y^{9}}$
Work Step by Step
$\frac{3}{2x}$=$\frac{3}{2x}$.1=$\frac{3}{2x}$.$\frac{2x}{2x}$=
$\frac{3}{9y^{5}}$=$\frac{3}{9y^{5}}$.1=
$\frac{3}{9y^{5}}$.$\frac{8y^{4}}{8y^{4}}$=
$\frac{24y^{4}}{72y^{9}}$
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