Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.3 - Adding and Subtracting Rational Expressions with the Same Denominator and Least Common Denominator - Exercise Set - Page 508: 37

Answer

Answer: $\frac{24b^{2}}{12ab^{2}}$

Work Step by Step

$\frac{6}{3a}$ = $\frac{6}{3a}$ $\times$ 1 = $\frac{6}{3a}$ $\times$ $\frac{4b^{2}}{4b^{2}}$ = $\frac{24b^{2}}{12ab^{2}}$
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