Answer
LCD=(x-1)(x+1)(3x+1)(4x+1)
Work Step by Step
$\frac{3x}{4x^{2}+5x+1}$, $\frac{5}{3x^{2}-2x-1}$
4$x^{2}$+5x+1=4$x^{2}$+x+4x+1=x(4x+1)+1(4x+1)=(x+1)(4x+1)
3$x^{2}$-2x-1=3$x^{2}$+x-3x-1=x(3x+1)-1(3x+1)=(x-1)(3x+1)
LCD=(x-1)(x+1)(3x+1)(4x+1)
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 7 - Section 7.3 - Adding and Subtracting Rational Expressions with the Same Denominator and Least Common Denominator - Exercise Set - Page 508: 32
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